Y^2=-25x^2+50x

Solution for Y^2=-25x^2+50x equation:

^2=-25Y^2+50Y

We move all terms to the left:

^2-(-25Y^2+50Y)=0

We add all the numbers together, and all the variables

-(-25Y^2+50Y)=0

We get rid of parentheses

25Y^2-50Y=0

a = 25; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·25·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*25}=\frac{0}{50}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*25}=\frac{100}{50}
=2
$